3q+1/3q^2+7q-40-5q+2/2q^2+3q-35

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Solution for 3q+1/3q^2+7q-40-5q+2/2q^2+3q-35 equation: 


q in (-oo:+oo)

(1/3)*q^2+(2/2)*q^2+3*q+7*q-(5*q)+3*q-40-35 = 0

(1/3)*q^2+(2/2)*q^2+3*q+7*q-5*q+3*q-40-35 = 0

4/3*q^2+8*q-75 = 0

DELTA = 8^2-(-75*4/3*4)

DELTA = 464

DELTA > 0

q = (464^(1/2)-8)/(4/3*2) or q = (-464^(1/2)-8)/(4/3*2)

q = 3/8*(4*29^(1/2)-8) or q = 3/8*(-4*29^(1/2)-8)

q in { 3/8*(-4*29^(1/2)-8), 3/8*(4*29^(1/2)-8) }

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